How many atoms are there in 5.00 mol of sulphur (S)?

3.01 × 10²⁴ atoms S

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

5.00 mol S

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

= 3.011 × 10²⁴ atoms S

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

3.011 × 10²⁴ atoms S ≈ 3.01 × 10²⁴ atoms S

b i think it’s a water wheel turning in a stream

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.