PLEASE HELP URGENT!! c) 2Al(s) + 3C12 (g) → 2AICI3
Reactant Side-
Product Side-
Oxidizing Agents
Reducing Agent

Reactant Side = Al + Cl₂  

Product Side = AlCl₃

Oxidizing Agents  = chlorine

Reducing Agent = aluminum

Explanation:

Chemical equation:

2Al + 3Cl₂     →      2AlCl₃

In this chemical equation Al and Cl₂ are reactants while AlCl₃ is product.

2Al° + 3Cl₂°     →      2Al⁺³Cl⁻¹₃

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

In given reaction Al is oxidized because oxidation increase from zero to +3. It is thus reducing agent.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

In given reaction chlorine is reduced because its oxidation state is decreased from zero to -1. Chlorine is oxidizing agent.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

i believe it is 40–40–20%

explanation:

idk i’m struggling too