1. How many grams in 7.57 moles of Calcium Nitrate (Ca(NO3)2)? grams (round to 3 sig figs)

2. How many moles are there in 56.7 grams of Carbon Tetrafluoride (CF4)?
moles (round to 3 sig figs)

3. Tums antiacids are made of calcium carbonate (CaCO3). Each Tums tablet contains 0.750 grams of Ca(CO3). If you eat 2 tums after a hefty Thanksgiving meal, how many moles of Calcium carbonate did you consume?
moles (round to 3 sig figs)

4. An oxygen canister contains 0.559 moles of Oxygen gas (O2). Calculate the mass of Oxygen in grams.
grams O2 (round to sig figs)

5. How many grams are present in 0.132 moles of Hydrocholric acid (HCl)?
grams (round to 3 sig figs)

6. If you have 98.078 grams of Sulfuric Acid, you have mole(s) of Sulfuric Acid (H2SO4).
moles (entire number

7. How many moles are present in 14.007 grams of Nitrogen gas (N2)?
moles (round to 3 sig figs)

8. How many grams would 2.43 moles of Ca(OH)2 weigh?
grams Ca(OH)2 (Round to 3 sig figs)

The answer to this is the 3rd choice!

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

The bergeron process.