6. A 4.0 L sample of methane gas is collected at 30.0 °C. Predict the volume of the sample at 0.0 °C.
Write out the answer

V₂ = 3.6 L

Explanation:

Given data:

Initial volume = 4.0 L

Initial temperature = 30.0°C

Final volume = ?

Final temperature = 0.0°C

Solution:

Initial temperature = 30.0°C (30+273=  303 K)

Final temperature = 0.0°C (0+273=  273 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 4.0 L × 273 K / 303 k

V₂ = 1092 L.K / 303 K

V₂ = 3.6 L

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.

6.4 cm (max) - 25 cm (min)