Silver nitrate and magnesium chloride react according to the following equation: 2AgNO3(aq) + MgCl2(aq) — 2AgCl(s) + Mg(NO3)2(aq)
What volume (in ml) of 0.247M MgCl2(aq) is required to react with 63.2 mL of 0.192M AgNO3(aq)?

V=24,3mL

Explanation:

1)n(AgNO3)=Cm*V=0.063l*0.192M=0.012

2)n(AgNO3)/2=n(MgCl2) => MgCl2=0.012/2=0.006

3)V(MgCl2)=n/Cm=0.006/0.247=0.0243L=24,3ml

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

5.6⋅10−^19  j

do you need the explaination?