A chemist prepares a solution by adding 253 mg of Co(NO3)2 (MW = 182.94 g/mol ) to a volumetric flask, and then adding water until the total volume of the contents of the flask reaches the calibration line that indicates 100 mL . Determine the molarity of the prepared solution.

The molarity of the prepared solution : 0.014 M

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

Where

M = Molarity

n = number of moles of solute

V = Volume of solution

mass of solute (Co(NO₃)₂) :253 mg = 0.253 g

moles of solute (Co(NO₃)₂) :

Volume of solution = 100 ml=0.1 L

The molarity :

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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