What will happen when a piece of magnesium metal is dropped into a beaker containing a l M solution of copper(1) chloride? Mg2+ + 2e = Mg(9) P = - 2.37 V
Cu2+ + 2e → Cu(9) ° = + 0.34 V
A. The magnesium will dissolve but nothing else will happen.
B. The magnesium will dissolve and the copper will be deposited
C. The copper will dissolve and the magnesium will be deposited
D. The magnesium will dissolve and chloride gas will be produced E. There will be no reaction,

What problem would a person have if the nucleic acid in one of his or her cells were damaged?

Consider the equilibrium system: 2icl(s) ⇄ i2(s) + cl2(g) which of the following changes will increase the total amount of of cl2 that can be produced? all of the listed answers are correct decreasing the volume of the container removing the cl2 as it is formed adding more icl(s) removing some of the i2(s)

The diagram below shows a cell placed in a solution.a cell is shown placed inside a beaker. it is labeled cell. the solution inside the beaker is labeled 40% salt solution and the solution inside the cell is labeled 20% salt solution.only water is allowed to move in and out of the cell. what will most likely happen to the cell? it will expand as water moves out of it. it will shrink as water moves out of it.it will expand as water moves into it. it will shrink as water moves into it.