How many grams of sulfur are in 3.54 g of H2S?

3.329 g

Explanation:

First you need to determine the molar mass of H2S which is 34.1 g/mol.

With that we know that to find the moles of H2S we just divide the mass of sample with the molar mass.

3.54 g / 34.1 g/mol = 0.103812317  mol of H2S

This means that there is also 0.103812317  mol of sulfur since there is 1 mole of sulfur per 1 mole of H2S.

The molar mass of sulfur is 32.065 g/mol and to find the mass of sulfur you need to multiply the molar mass with the moles of the compound.  

0.103812317  mol * 32.065 g/mol = 3.329 g of sulfur

Let me know if you get something else or if something is unclear in the comments so that we can figure it out.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.