Consider the reaction: 2 h2o (> 2 h2 (g) + o2 (g). δh=483.6 kj/mol. if 2 moles of h2o (g) are converted h2(g) and o2(g) against a pressure of 1 atm at 125 degrees celcius what is δe of reaction?

Answer : The value of of the reaction is, 480.29 KJ.

Explanation :

Formula used :

where,

= internal energy of the reaction = ?

= enthalpy of the reaction = 483.6 KJ/mole = 483600 J

= change in the moles of the reaction = Moles of product - Moles of reactant = 3 - 2 = 1 mole

R = gas constant = 8.314 J/mole.K

T = temperature =

Now put all the given values in the above formula, we get:

Therefore, the value of of the reaction is, 480.29 KJ.

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