A piece of unknown metal absorbed 790.24 J of heat as it was heated from 40.0°C to 72.0°C. If the piece of metal weighed 55.0 g, what is the identity of the metal?

Given metal is iron

Explanation:

Given data:

Heat absorbed = 790.24 J

Initial temperature = 40.0 °C

Final temperature = 72.0 °C

Mass of metal = 55.0 g

Identity of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 72.0°C - 40.0°C

ΔT =  32 °C

790.24 J = 55 g ×c ×  32 °C

790.24 J = 1760 g. °C  ×c

c = 790.24 J /1760 g. °C

c = 0.449 J/g. °C

The specific heat capacity of iron is 0.449 J/g. °C thus, given metal is iron.

they are made of gases.

they have a spherical shape.

they make energy through fusion.

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.