How many moles are present in 1.2L of a 0.1 M NaCl solution?

0.12 mole.

Explanation:

From the question given above, the following data were obtained:

Molarity of NaCl solution = 0.1 M

Volume of NaCl solution = 1.2 L

Mole of NaCl =.?

Molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

Thus, we can obtain the mole of NaCl in the solution by using the above formula as follow:

Molarity of NaCl solution = 0.1 M

Volume of NaCl solution = 1.2 L

Mole of NaCl =.?

Molarity = mole /Volume

0.1 = mole of NaCl /1.2

Cross multiply

Mole of NaCl = 0.1 × 1.2

Mole of NaCl = 0.12 mole

Therefore, 0.12 mole of NaCl is present in the solution.

the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation:

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