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Chemistry, 01.12.2020 17:40 jtroutt74

A 100.0 mL solution of 0.0200 M Fe3+ in 1 M HClO4 is titrated with 0.100 M Cu+, resulting in the formation of Fe2+ and Cu2+. A Pt indicator electrode and a saturated Ag∣∣AgCl electrode are used to monitor the titration. Calculate the values of for the cell after each of the given volumes of the Cu+Cu+ titrant have been added.

10.0 ml E = ? V

19.5 ml E = ? V

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A 100.0 mL solution of 0.0200 M Fe3+ in 1 M HClO4 is titrated with 0.100 M Cu+, resulting in the for...
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