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Chemistry, 29.11.2020 21:50 fqjenfiq6959

From the reaction C10H8(s) + 12O2(g) = 10CO2(g) + 4H2O(l) ΔrH° = –5153.0 kJ mol–1 and the enthalpies of formation of CO2 and H2O (–393.5 kJ mol–1 and –285.8 kJ mol–1, respectively) calculate the enthalpy of formation of naphthalene (C10H8).

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From the reaction C10H8(s) + 12O2(g) = 10CO2(g) + 4H2O(l) ΔrH° = –5153.0 kJ mol–1 and the enthalpies...
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