Question 3. Starting with acetylene , devise a scheme to prepare 1-chloroheptanol
. There is more
than one way to complete this synthesis
. It can be completed in as few as three reactions. You
can use any alkyl halides as needed as sources of carbon atoms. PLEASE EXPLAIN THE PROCESS. I’m begging. Please.

See explanation and image attached

Explanation:

Starting from acetylene, we can react the substrate with methyl iodide in the presence of sodamide and ammonia. We then obtain propyne which then undergoes a similar reaction using butyl iodide to yield 2-heptyne.

This may now be reduced using hydrogen and platinum to yield heptane. Heptane is chlorinated in the presence of light to yield a mixture of products of which 1-chloroheptane is one.

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

mark brainliest and have a great day!

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i