For an aqueous solution of sucrose (C12H22O11), determine: (a) the molarity of 3.30 L of a solution that contains 225.0 g of sucrose M (b) the volume of this solution that would contain 4.30 mole of sucrose L (c) the number of moles of sucrose in 1.00 L of this solution mol C12H22O11

a) Molarity = 0.199M

b) 21.6L of solution

c) 0.199 moles of sucrose in 1L

Explanation:

a) Molarity is the ratio of moles of solute (sucrose) in volume of solution (3.30L):

Moles sucrose -Molar mass: 342,3g/mol-:

225.0g * (1mol / 342,2965g) = 0.6573 moles

Molarity = 0.6573 moles / 3.30L

b) 0.199M means 0.199 moles in 1L. 4.30 moles are in:

4.30 mol * (1L / 0.199mol) = 21.6L of solution

c) By definition, there are 0.199 moles of sucrose in 1L. This is the meaning of 0.199M

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