if one species of rabbit, the gene for brown fur ( B) is dominant, while the gene for black fur ( b) is recessive. One rabbit has the dominant allele for brown fur and the recessive allele for black fur. Another rabbit has two recessive alleles. If the two rabbits have offspring, what are the odds of one of the offspring having brown fur?

1/2

Explanation:

According to this question, the gene coding for fur color in rabbits contains two alleles viz: alelle for brown fur ( B) is dominant, while the allele for black fur ( b) is recessive. This means that an heterozygous rabbit (Bb) will have brown fur.

Based on the question, one rabbit has the dominant allele for brown fur and the recessive allele for black fur i.e genotype Bb, another rabbit has two recessive alleles i.e. genotype bb. If these two rabbits cross i.e. Bb × bb, the proportion of the offsprings produces will have Bb, Bb, bb and bb genotype.

Bb is dominant, hence, 1/2 of the offsprings will be brown furred.

one species of rabbit, . the two rabbits have offspring, what are the

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

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