CAN you please solve this? please please please

115.2ml of water should be added.

Explanation:

We start with 46.2ml of 1.396M sugar solution;

We want to end up with a 0.56M sugar solution;

Finding the number of moles in the sugar solution to begin with:

moles of sugar in solution initially = 46.2 × 1.396 = 64.4952

Vd = volume of desired solution (i.e. 0.56M solution)

w = volume of water added

Vd = (46.2 + w)

Using the mol = vol' × conc'n equation:

64.4952 = Vd × 0.56

Vd = 64.4952/0.56

Vd = 115.17

46.2 + w = 115.17

w = 115.17 - 46.2

w = 68.97ml

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied