Select the lewis structure for xeo2f2 which correctly minimizes formal charges.

The correct Lewis structure allows all the atoms involved in the bond to have eight electrons in the valence layer.

You can see this structure in the image attached below.

We can arrive at this answer because:

In this case, we can observe the figure below and count the number of electrons that each atom reaches with the covalent bond between them. This will show us that each has eight electrons, which is the correct structure for .

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explanation and image attached

Explanation:

Our aim is to draw a structure of XeO2F2 whith the least formal charges. We must remember that the compound has 34 valence electrons.

To obtain the least formal charges then Xe must have a total of twelve electrons on its valence shell instead of eight.

The other atoms around the central Xe atom are arranged as shown in the image attached.

Image Credit: UCLA

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explanation: i will tell you how to if u answer my question.

the answer would be b i believe