How much energy is required to raise 10.0 grams of water (c=4.18j/gC) by 20*C?

Q = 836 J

Explanation:

Given data:

Mass of water = 10.0 g

Temperature increased =ΔT = 20°C

Specific heat  capacity of water = 4.18 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Q = 10.0 g × 4.18 J/g.°C  × 20°C

Q = 836 J