How many grams of Phosphorus is required to complete combustion of 40g Oxygen P+O2-mm>P2O5 . Please balance

Mass = 31 g

Explanation:

Given data:

Mass of phosphorus required = ?

Mass of oxygen = 40 g

Solution:

Chemical equation:

4P + 5O₂     →     2P₂O₅

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 40 g/ 32 g/mol

Number of moles = 1.25 mol

Now we will compare the moles of P and oxygen.

                      O₂             :            P

                       5              :            4

                      1.25          :         4/5×1.25 = 1

Mass of phosphorus:

Mass = number of moles × molar mass

Mass = 1 mol × 31 g/mol

Mass = 31 g