The image above shows a gas held in a chamber with a fixed volume. The gas begins with a temperature 333 K and a pressure of 4.00 atm (green) that increases to 7.65 atm (orange) as the gas is heated. What is the temperature of the gas when the pressure increases to 7.65 atm?

636.86 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T1) = 333 K

Initial pressure (P1) = 4 atm

Final pressure (P2) = 7.65 atm

Final temperature (T2) =?

NOTE: The volume is constant.

Since the volume is constant, we can obtain the new temperature the gas by using the following formula as illustrated below:

P1 /T1 = P2 /T2

4/333 = 7.65/T2

Cross multiply

4 × T2 = 333 × 7.65

4 × T2 = 2547.45

Divide both side by 4

T2 = 2547.45 / 4

T2 = 636.86 K

Therefore, the new temperature of the gas is 636.86 K

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