how many joules are needed to warm 25.5 grams of water from 14.0°C to 22.5°C? the heat capacity of liquid water is 4.184J/g°C

Q = 906.882 J

Explanation:

Given data:

Mass of water = 25.5 g

Initial temperature = 14.0 °C

Final temperature = 22.5 °C

Specific heat capacity of water = 4.184 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 22.5 °C - 14.0 °C

ΔT = 8.5 °C

Q = 25.5 g × 4.184 J/g.°C ×  8.5 °C

Q = 906.882 J

answer

fusion: the energy source of stars. the energy released from the collapse of the gas into a protostar causes the center of the protostar to become extremely hot. when the core is hot enough, nuclear fusion commences. fusion is the process where two hydrogen atoms combine to form a helium atom, releasing energy.

hope it

the answer is a. co2, this would be colder than the : )

explanation: