What is the mass in grams of 14.2 liters of sulfur dioxide gas at STP?

Mass = 40.4 g

Explanation:

Given data:

Mass in gram = ?

Volume of SO₂ = 14.2 L

Temperature = standard = 273 K

Pressure =  standard = 1 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × 14.2 L = n × 0.0821 atm.L/ mol.K   × 273 K

14.2 atm.L = n ×  22.41 atm.L/ mol

n = 14.2 atm.L/22.41 atm.L/ mol

n = 0.63 mol

Mass of sulfur dioxide:

Mass = number of moles × molar mass

Mass = 0.63 mol × 64.1 g/mol

Mass = 40.4 g

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.