Calculate the volume in liters of oxygen gas at STP required to produce 19.5 g of carbon dioxide. 2 C2H2(g) + 5 O2(g) —> 4 CO2(g) + 2 H2O(g)

Answer should be written as XX. X L O2

there all right good

explanation:

d.) circle motion requires a force to give it a centripetal acceleration.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3