How many grams (of mass m) of glucose are in 205 mL of a 5.50% (m/v) glucose solution?

Ok, I figured it out...

First one is 355 * 5.5% = 19.5 g

then, 18.5% *2.49 L *1000 (to make mL) = 461 mL

then, 42.4/6% = 707 mL

Explanation:

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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