A. Briefly explain how a loss of water by evaporation would affect the initial calculation of the solubility of your salt. B. Would this initial evaporation affect the calculated solubility of your salt at each subsequent experimental saturation temperature, or just the initial temperature? Explain.

Following are the solution to this question:

Explanation:

Please find the complete question in the attached file.

In point a:

When some water evaporates from its mixture, then when a thick layer is initiated, it reduces salt solubility, but sodium remains unclear throughout the solution (ppt solte).  

In point b:

Ksp is measured by calculating the mass of its solvent reduction process, decreasing salt solubility and hence decreasing Ksp.  

In point c:

From of the graph are calculated by v/s lnKsp  

(decrease) LnKsp may shift,  

So, both are decreasing

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

2b2t

explanation:

2b2t