9. When 4.46 moles of ethylene, C2H4, burns in oxygen to give carbon dioxide and water, how many grams of carbon dioxide are formed?
C2H4 + 3 O2 → 2 H2O + 2 CO2
How many grams of carbon dioxide are formed??

4.46 moles of Ethylene will produce 392.48 grams of Carbon dioxide.

Explanation:

The reaction is as follows

C2H4 + 3 O2 → 2 H2O + 2 CO2

For complete combustion of Ethylene 1 mole of ethylene gives 2 moles of Carbon dioxide.

using unitary method

1 C2H4 => 2CO2

4.46 of C2H4  => 2*4.46 CO2

                         =  8.92 CO2

No of moles  = given mass(w) /molar mass(M)

Molar mass of CO2 = 44g

8.92 = W / 44

W = 8.92 * 44

    = 392.48g

So 4.46 moles of Ethylene will produce 392.48 grams of Carbon dioxide.

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