A sumo wrestler is 330 pounds. How much force does the earth exert on him? (Weight)

1336.4N

Explanation:

Given parameters:

Mass of the sumo wrestler  = 330pounds

Unknown:

Amount of force the earth exerts on the wrestler  = ?

Solution:

The force the earth exerts on the wrestler is the weight of the man;

  Weight  = mg

where;

 m is the mass

 g is the acceleration due to gravity

   Now,

 let us convert from pounds to kg;

          2.2pounds  = 1kg

         300 pounds  =   = 136.4kg

Weight  = 136.4kg x 9.8m/s²  = 1336.4N

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j