Sulfur trioxide decomposes to form sulfur dioxide and oxygen, like this: SO3(g)SO2(g) + O2(g) Write the pressure equilibrium constant expression for this reaction.

Kp = P(SO2)  *   P(O2)  / P(SO3)

Explanation:

The equation is given as;

SO3(g)  --> SO2(g) + O2(g)

In the pressurer equilibrium constant expression, only the gaseous entities are considered.

It is given as;

Kp = P(products)   /  P(reactants)

Product are  SO2(g) and O2(g)

Reactant is SO3(g)

Kp = P(SO2)  *   P(O2)  / P(SO3)

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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the answer is barium and copper bromide