Use the half-reactions of the reaction Upper A u (upper O upper H) subscript 3 plus upper H upper I right arrow upper A U plus upper I subscript 2 plus upper H subscript 2 upper O. to answer the questions. Reduction half-reaction:Upper A u superscript plus 3, plus 3 e superscript minus right arrow upper A u.
Oxidation half-reaction:2 upper i right arrow upper I subscript 2 plus 2 e superscript minus.

How many electrons does each gold atom gain?
How many electrons does each iodine atom lose?
What is the total number of electrons that are moved in the oxidation-reduction reaction?

Complete the final balanced equation based on the half-reactions.
_Au(OH)3+_HI Right arrow_ Au +_ I2 + _ H2O

How many electrons does each gold atom gain?

  3

How many electrons does each iodine atom lose?

   1

What is the total number of electrons that are moved in the oxidation-reduction reaction?

   6

Complete the final balanced equation based on the half-reactions.

2Au(OH)3+6 HI 2 Au +1 3I2 +6 H2O

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.

gold is my favorite solid.