Solve each of the following problems using dimensional analysis.

453.6 g

Explanation:

The following data were obtained from the question:

Mole of Ag = 4.2 moles

Weight (in grams) of Ag =?

Thus, we can obtain the weight in grams of Ag by doing the following:

Mole of Ag = 4.2 moles

Molar mass of Ag = 108 g/mol

Mass of Ag =.?

Mole = mass /Molar mass

4.2 = mass of Ag /108

Cross multiply

Mass of Ag = 4.2 × 108

Mass of Ag = 453.6 g

Thus, the weight (in grams) of 4.2 moles of Ag is 453.6 g

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

sry but any answer choices