Draw a structural formula for the product formed upon hydroboration/oxidation of the alkene below. CH3CH2CH2CHCH2

CH3-CH2-CH2-CH2-CH2-OH. (1-PENTANOL)

Explanation:

The given compound is Pente-1-ne

Hydroboration oxidation reagent - BH3 +H2O2 + OH-

The reaction is initiated by boron hydride which attacks the terminal carbon because the middle carbon + charge will be stabilized by +I effect of the parent carbon chain. This similar process will happen thrice and all the hydrogens of Boron hydride will be lost and carbon chain of Pent-1-ene will be attached to boron and it will form TRIPENTYL BORANE, Then we will add H2O2+ OH- and finally OH- will be attached to the parent carbon chain and

1-PENTANOL will be formed.

CH3-CH2-CH2-CH=CH2 + HBO → CH3-CH2-CH2-CH2-CH2-OH

                                                               1-PENTANOL

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.