How do you solve this Given the enthalpies of reaction

S(s)+O2(g)→SO2(g) ΔH = -297 kJ

2S(s)+3O2(g)→2SO3(g) ΔH=-791kJ

Calculate the enthalpy change (ΔH) for the following reaction using the data above and Hess's Law:

2SO2+O2⟶2SO3

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons

1.solid

2.carbon dioxide

3.helium

it’s previous models   because when i picked that son of a gun’s answer it was wrong look for previous models because they might make it a different letter