If an ideal gas has a pressure of 4.03 atm, a temperature of 309 K,
and a volume of 35.01 L,
how many moles of gas are in the sample?

PV=nRT where P=pressure in atm, V=volume is liters, n=numbber of moles, R=gas constant, 0.08206 L-atm/mole KL, and T=temperature in K (273 + C).  So (5.67atm)(99.39L)=n(0.08206 L-atm/mol.K)(328.94K), solve for n, the number of moles, n=20.9 moles.

Explanation:

it would be a gas formation