In an The mass of a small stone was 27 g.
. The reading of the level of water in the graduated cylinder was 10 cm before the
stone was placed into the overflow can.
The reading of the level of water was 19 cm after the stone was placed into the
overflow can
(a) Calculate the volume of the stone.
(b) Calculate the density of the stone.

d = 3 g/cm³

Explanation:

Given data:

Mass of stone = 27 g

Volume of water = 10 cm³

Volume of water+ stone = 19 cm³

Volume of stone = ?

Density of stone = ?

Solution:

Volume of stone = total volume - volume of water

Volume of stone = 19 cm³ -  10 cm³

Volume of stone = 9 cm³

Density of stone:

d = m/v

d = 27 g/ 9 cm³

d = 3 g/cm³

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

the answer is 0.8m.

by: nicholas