In the reaction of Zn with HCl, 140.15 g of ZnCl2 was actually formed, although the theoretical yield was 143 g. What was the percent yield?

Zn + 2HCl ➡ ZnCl2 + H2

Percent yield = 98%

Explanation:

Given data:

Actual yield of ZnCl₂ = 140.15 g

Theoretical yield of ZnCl₂  = 143 g

Percent yield = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield )× 100

Percent yield = (140.15 g/ 143 g)× 100

Percent yield = 0.98 × 100

Percent yield = 98%

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.