How many grams of C are required to react with 97.1 g of Fe2O3?

21.9 g C

Explanation:

Fe₂O₃  +  3 C  ⇒  2 Fe  +  3 CO

This is your chemical equation.  

To find the grams of C required, first convert grams of Fe₂O₃ to moles using the molar mass (159.69 g/mol).  

(97.1 g)/(159.69 g/mol) = 0.608 mol Fe₂O₃

Then, use the mole ratio between Fe₂O₃ and C to convert moles of Fe₂O₃ to moles of C.  You can find the mole ratio by looking at the chemical equation.

(0.608 mol Fe₂O₃) × (3 mol Fe₂O₃/1 mol Fe₂O₃) = 1.824 mol C

You can then convert moles of C to grams using the molar mass (12.01 g/mol).

(1.824 mol) × (12.01 g/mol) = 21.9 g

warm front forms when a moist, warm air mass slides up and over a cold air mass. as the warm air mass rises, it condenses into a broad area of clouds. a warm front brings gentle rain or light snow, followed by warmer, milder weather.

hope i !