a wet 43.2 g sample of copper sulfate heptahydrate is heated until only copper sulfate remains. the mass of the water lost is 34.1 g. what is the mass of copper sulfate

The mass of copper sulphate that is produce from a wet 43.2 g sample of copper sulphate heptahydrate that is heated until only copper sulphate remains (mass of water lost is 34.1 g)  is 9.1 grams.

Using the law of conservation of matter, the mass of the reactant is equals to the mass of the product.

Therefore,

CuSO₄7H₂O → CuSO₄ + 7H₂O

mass of CuSO₄7H₂O = 43.2 g

mass of CuSO₄ = x

mass of H₂O = 34.1 g

mass of  CuSO₄ = 43.2 - 34.1

mass of  CuSO₄ = 9.1 g

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9.1g

Explanation:

Given parameters:

Mass of copper sulfate heptahydrate  = 43.2g

Mass of water lost  = 34.1g

Unknown:

Mass of copper sulfate = ?

Solution

The copper sulfate heptahydrate is made up of the copper sulfate and water of crystallization which makes it wet.

Mass of copper sulfate heptahydrate  = mass of copper sulfate + mass of water

Mass of copper sulfate = mass of copper sulfate heptahydrate - mass of water

Mass of copper sulfate = 43.2g  - 34.1g = 9.1g