Calculate the concentration of sodium hydroxide solution obtained when: 1.(a) 2 ml of 0.1 mol/l NaOH is added to 25 ml of water

(b) 10 g of NaOH are added to 50 ml of water

moles Ca(OH)2 ---> (0.10 mol/L) (0.060 mL) = 0.0060 mol

moles HNO3 ---> (0.10 mol/L) (0.050 mL) = 0.0050 mol

Ca(OH)2 + 2HNO3 ---> Ca(NO3)2 + 2H2O

Two HNO3 are required to neutralize one Ca(OH)2, so only 0.0025 mol of Ca(OH)2 will be neutralized.

0.0060 mol minus 0.0025 mol = 0.0035 mol of Ca(OH)2 remaining

Ca(OH)2 and H2SO4 react in a 1 to 1 molar ratio, so 0.0035 mol of H2SO4 is required.

volume H2SO4 ---> 0.0035 mol / 0.10 mol/L = 0.035 L = 35.0 mL

Explanation:

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.