For the reaction: Agl(s) + V2Br2(g) AgBr(s) + /12 ()
AH° = -54.0 kJ
And:
AH® for AgBr(s) = -100.4 kJ/mol
AH° for Br2(g) = +30.9 kJ/mol
Therefore value of AH for Agl(s) must be:
+61.8 kJ/mol.
-61.8 kJ/mol.
O-123.5 kJ/mol.
+77.3 kJ/mol.
O-77.3 kJ/mol.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

b) nuclear ive learned that in a pedtrodic table