a sample of carbon dioxide gas occupies a volume of 20 L at standard temperature and pressure (STP). what will be the volume of a sample of argon gas that has the same number of moles and but tripled the absolute temperature?

Volume of Argon = 59.972 L

In general, the gas equation can be written  

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

At STP(0 C, 1 atm), 1 mol gas= 22.4 L

so for 20 L

For Argon

P = 1 atm

T = 273 K x 3 =819 K (tripled)

n = 0.893 (the same number of moles)

R = 0.082 L/atm.mol K

what's the question?

explanation:

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles