For the following reaction at equilibrium SO3(g) + NO(g) = SO2(g) + NO2(g)It is found that [SO2] = 0.70 M and [NO] = 1.20 M. Calculate the equilibrium constant for the readction knowing that the initial concentration were [SO3] = 2.55 M and [NO] = 1.90 M.

Explanation:

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In this case, for the undergoing chemical reaction, we can write the equilibrium expression via:

Whereas the equilibrium concentration of both SO3 and NO are 2.55 M and 1.90 M respectively, it means that the extent of reaction is:

Because the equilibrium expression in terms of the reaction extent is:

It means that the concentration of SO3, NO, SO2 and NO2 at equilibrium are:

Thus, the equilibrium constant for such reaction is:

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