Write the thermochemical equation for the combustion of acetylene, C2H2 (g), in oxygen, for which the standard enthalpy of reaction is -1300 kJ per mole of acetylene.

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)   ΔH° = -1300 kJ/mol

Explanation:

In the combustion of acetylene, it reacts with oxygen to produce carbon dioxide and water. The corresponding chemical equation is:

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)

The thermochemical equation includes the balanced chemical equation, stating the states of aggregation and the enthalpy of the reaction.

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)   ΔH° = -1300 kJ/mol

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .