The gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 K. If the pressure decreases to 3.20 atm, what is the temperature of the gas in kelvin

T₂  = 244.5 K

Explanation:

Given data:

Initial pressure = 3.90 atm

Initial temperature = 298 K

Final pressure = 3.20 atm

Final temperature = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

3.90 atm / 298 K = 3.20 atm/T₂

T₂  =  3.20 atm × 298 K / 3.90 atm

T₂  = 953.6atm. K /3.90 atm

T₂  = 244.5 K