**BRAINLIEST** I already figured out half of it.

1. Calculate the actual yield of magnesium oxide for each trial.
Trial 1: 0.585g
Trial 2: 0.417

2. Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.

Trial 1: 0.357g
Trial 2: 0.254

3. Determine the percent yield of MgO for your experiment for each trial.

Trial 1:
Trial 2:

4. Determine the average percent yield of MgO for the two trials.
Trial 1 Trial 2
Mass of empty crucible with lid 26.679g 26.679g
Mass of Mg metal, crucible, and lid 27.036g 26.033g
Mass of MgO, crucible, and lid 27.264g 27.096