In Part B, we determined the water hardness of a water sample by combining the water sample with a 10.00 mL sample of calcium chloride, then titrating with EDTA. If we substituted distilled water for the water sample, how would our titration have been different? Would the volume of EDTA required to reach the end point have been greater than, less than, or the same as the volume we used with our combined water sample? Explain.

The definition is defined throughout the clarification section beneath, and according to the particular circumstance.

Explanation:

Although water samples were supplemented with purified water, the amount of EDTA has would be smaller. Since there are fewer ions throughout purified water, most of the ions are eliminated throughout distillation, less utilized EDTA. Complex calcium formation including EDTA will be less complex. Samples used throughout the starting include several Ca⁺², Mg²⁺ ions that have not been found in pure water, causing fewer EDTA volume to enter the final stages.

10.063g / 10.00 ml = 1.0063 g/ml which rounds off to 4 sig figs as: 1.006 g/ml

Sorry i dont understand the question can you rephase it?