1.)A photon has a wavelength of 1.95 x10^-11 m. What is the frequency? a.)Using your answer, find the energy of that photon

Explanation:

Given parameters:

Wavelength of photon = 1.95 x 10⁻¹¹m

Unknown:

Frequency of the wave  = ?

Energy of the photon = ?

Solution:

The frequency and wavelength of a wave are related by the expression;

   C = Fλ

C = speed of light  = 3 x 10⁸m/s

F = frequency

λ = wavelength

 Insert the parameters and solve;

    3 x 10⁸  = F x 1.95 x 10⁻¹¹

       F  =   = 1.54 x 10¹⁹Hz

Energy of the photon is related to frequency using the expression below;

  E  = hF

h is the Planck's constant = 6.634 x 10⁻³⁴m²kg/s

Insert the parameters and solve;

    E = 6.634 x 10⁻³⁴ x 1.54 x 10¹⁹   = 1.02 x 10⁻¹⁴J

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm