Calculate the mass of 1.35 moles of sodium chloride

78.894g of NaCl

Explanation:

This requires some dimensional analysis:

Using the molar mass of NaCl we get the answer we are looking for.

1.35 Moles of NaOH * = 78.894 g of NaCl

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation: