How many grams of Fe can be produced when 6.50 g of Fe2O3 reacts?

Mass of Fe produced = 4.468 g

Explanation:

Given data:

Mass of Fe produced = ?

Mass of Fe₂O₃ react = 6.50 g

Solution:

Chemical equation:

2Fe₂O₃        →     4Fe + 3O₂

Number of moles of Fe₂O₃ ;

Number of moles = mass/molar mass

Number of moles = 6.50 g/159.69 g/mol

Number of moles = 0.04 mol

Now we will compare the moles of iron and ironoxide.

                    Fe₂O₃             :             Fe

                         2                :              4

                       0.04             :             4/2×0.04 = 0.08 mol

Mass of iron produced:

Mass = number of moles × molar mass

Mass = 0.08 mol × 55.85 g/mol

Mass = 4.468 g