How many moles of hydrogen are in 4.70 moles of C12H22O11

103.4 moles of hydrogen

Explanation:

Given data:

Moles of C₁₂H₂₂O₁₁ = 4.70 mol

Number of moles of hydrogen present = ?

Solution:

one mole of C₁₂H₂₂O₁₁  contain 22 moles of hydrogen. Thus in order to determine total number of moles in 4.70 moles of C₁₂H₂₂O₁₁ we will multiply the 22 moles of hydrogen with 4.70 moles of C₁₂H₂₂O₁₁.

1 mole of C₁₂H₂₂O₁₁ = 22 moles of Hydrogen

4.70  × 22 moles

103.4 moles of hydrogen

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.